How many 5.9 inch by 19.6 inch tiles are needed to cover 50 square feet?

Answer 1

The area of each tile is 5.9 inches x 19.6 inches = 115.64 sq inches

The area to be covered = 50 square feet = 50*144 = 7200 sq inches

So minimum requirement = 7200/115.64 = 62.26 or 63 tiles.

However, this assumes that most of the offcuts are used. This may result in some are looking like a mosaic. It is also assumed that there is no space between tiles for grouting.

The area of each tile is 5.9 inches x 19.6 inches = 115.64 sq inches

The area to be covered = 50 square feet = 50*144 = 7200 sq inches

So minimum requirement = 7200/115.64 = 62.26 or 63 tiles.

However, this assumes that most of the offcuts are used. This may result in some are looking like a mosaic. It is also assumed that there is no space between tiles for grouting.

The area of each tile is 5.9 inches x 19.6 inches = 115.64 sq inches

The area to be covered = 50 square feet = 50*144 = 7200 sq inches

So minimum requirement = 7200/115.64 = 62.26 or 63 tiles.

However, this assumes that most of the offcuts are used. This may result in some are looking like a mosaic. It is also assumed that there is no space between tiles for grouting.

The area of each tile is 5.9 inches x 19.6 inches = 115.64 sq inches

The area to be covered = 50 square feet = 50*144 = 7200 sq inches

So minimum requirement = 7200/115.64 = 62.26 or 63 tiles.

However, this assumes that most of the offcuts are used. This may result in some are looking like a mosaic. It is also assumed that there is no space between tiles for grouting.

Answer 2

The area of each tile is 5.9 inches x 19.6 inches = 115.64 sq inches

The area to be covered = 50 square feet = 50*144 = 7200 sq inches

So minimum requirement = 7200/115.64 = 62.26 or 63 tiles.

However, this assumes that most of the offcuts are used. This may result in some are looking like a mosaic. It is also assumed that there is no space between tiles for grouting.