8 with 1 remaining 49 - 1 = 48 = 6 x 8
5 with 4 remaining 34 - 4 = 30 = 6 x 5
4 times with 52 remaining
7 with 3 remaining 87 - 3 = 84 = 12 x 7
Well, isn't that a happy little question! Let's see, if you take 87 and divide it by 15, you'll find that 15 can go into 87 about 5 times with a remainder of 12. Remember, there are no mistakes, just happy little accidents in math!
To determine how many times 9 can go into 87, you would perform division: 87 รท 9 = 9. This means that 9 can go into 87 nine times without any remainder. Each time 9 is divided into 87, the result is 9.
The 6s sublevel can hold a maximum of 2 electrons.
14 with 3 remaining 87 - 3 = 84 = 6 x 14
50
20.
5
27