Q: How many 9's are sandwiched between 6 and 7?

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6 of them with a remainder of 4

You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6

There are 7 of them as 9 x 7 = 63.

33 divided by 9 equals 3 with a remainder of 6

4 and 6/9 so 4 and 2/3 I believe that is correct.

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Exactly 6 of them

6 of them with a remainder of 4

You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6

There are 7 of them as 9 x 7 = 63.

33 divided by 9 equals 3 with a remainder of 6

4 and 6/9 so 4 and 2/3 I believe that is correct.

Well 6x6=36 how many 9s go in to 36? 4 Hope this helped

(9*9)+(9+9)+(9/9) = 100

there is no check valve only a diaphragm pump on the side of the engine. if this is what you are talking about it is a diaphragm sandwiched between two aluminum blocks and then a gasket between that and the engine.

9s+6s-12s=24... Ignore the 's' for a moment giving the sum 9+6-12=24 - This results in the answer 3 x 'something' = 24. Therefore s=8 !

It's a simple linear equation in one unknown ( 's' ).You can find the value of 's' that makes it true as follows:38s + (7 - 9s) = 35s + (3 - 13)Dump the parentheses:38s + 7 - 9s = 35s + 3 - 13Combine like terms on each side:29s + 7 = 35s - 10Add 10 to each side:29s + 17 = 35sSubtract 29s from each side:17 = 6sDivide each side by 6:17/6 = ss = 2 and 5/6

9,18,27,36,45,54,63,70 and count the numbers as 1 2 3 4 5 6 7 8 9 how many 9s