actually its 313.
313 Btu
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
To convert 1 pound of ice at 32°F to 1 pound of water at 32°F, you need to supply 144 BTUs. This energy is required to overcome the latent heat of fusion, which is the energy needed to change ice into water without changing its temperature.
To calculate the BTUs removed per hour, use the formula: BTUs = flow rate (lbs/min) × temperature change (°F) × 1.0 (specific heat of water). First, convert the flow rate to pounds per hour: 10 lbs/min × 60 min/hour = 600 lbs/hour. Then, calculate the BTUs: BTUs = 600 lbs/hour × 15°F × 1.0 = 9,000 BTUs/hour. Thus, 9,000 BTUs of heat are removed per hour.
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
144
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
313 Btu
To determine the BTUs that must be removed from one pound of water at 200°F to convert it to ice at 30°F, we need to account for several steps: cooling the water from 200°F to 32°F (the freezing point), the phase change from water to ice at 32°F, and then cooling the ice from 32°F to 30°F. Cooling the water from 200°F to 32°F requires about 168 BTUs (1 BTU cools 1 pound of water by 1°F). Freezing the water at 32°F requires the removal of 80 BTUs (latent heat of fusion). Cooling the ice from 32°F to 30°F requires an additional 2 BTUs. In total, approximately 250 BTUs must be removed (168 + 80 + 2 = 250 BTUs).
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
It takes approximately 144 BTUs to change one pound of ice at 20°F to water at 212°F, and an additional 970 BTUs to change the water to steam at 220°F, for a total of 1114 BTUs.
It takes approximately 970 BTUs to convert one pound of water at 212°F (100°C) to steam at the same temperature.
To convert water at 200°F to ice at 30°F, you need to remove 1 BTU to cool water from 200°F to 32°F to become ice. Then, you need to remove 144 BTUs to cool the ice from 32°F to 30°F. So, total BTUs needed to remove from one pound of water at 200°F to end up as ice at 30°F is 144 + 1 = 145 BTUs.
One pound of steam at 212 degrees Fahrenheit contains 1150 BTUs of energy.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
To raise the temperature of 1 pound of water by 1 degree Fahrenheit, it requires 1 BTU (British Thermal Unit). Therefore, to heat water by 10 degrees, it would require 10 BTUs per pound of water. This value may vary slightly depending on the specific heat capacity of the water.
To convert 1 pound of ice at 32°F to 1 pound of water at 32°F, you need to supply 144 BTUs. This energy is required to overcome the latent heat of fusion, which is the energy needed to change ice into water without changing its temperature.