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How many calories are required to raise the temperature of 1 g of water by 5 degrees C?

It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.


) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?

one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius


How many calories are needed to raise the temp of 8.1 g of water 20 degrees Celsius?

The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.


How many calories are required to raise the temperature of 1 g of water by 5drgress c?

1 Calorie is equal to 1000 calories one is a big C the other is a small c and 1 Calorie is needed to raise 1gram of water; 1 Degree C* so your answer is 5 Calories or 5000calories


How many Calories are needed to heat up a 2 liter bottle of liquid from 0 degrees to 100 degrees Celsius?

The amount of calories needed to heat up a substance can be calculated using the specific heat capacity of the substance. For water, the specific heat capacity is 1 calorie/gram°C. A 2-liter bottle of water weighs around 2000 grams. To raise the temperature of 2000 grams of water from 0°C to 100°C, you would need approximately 200,000 calories.

Related Questions

Is temperature measured in calories?

No, temperature is not measured in calories. Temperature is typically measured in degrees Celsius (°C) or degrees Fahrenheit (°F), while calories are units of energy related to the amount of heat required to raise the temperature of one gram of water by one degree Celsius.


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


How many calories are required to raise the temperature of 1 g of water by 5 degrees C?

It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.


How many calories to raise i gram of water 40 degrees c?

To raise 1 gram of water by 40 degrees Celsius, you need 40 calories. This is based on the specific heat capacity of water, which is approximately 1 calorie per gram per degree Celsius. Therefore, for a temperature increase of 40 degrees, you multiply 40 degrees by 1 calorie per gram.


How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?

(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.


) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?

one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius


4 kg of ice at 0 degrees Celsius is converted to steam at 100 degrees Celsius How much heat is needed?

To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.


The amount of dietary Calories in one hard-boiled egg could raise the temperature of?

1,000 grams of water by 75 degrees Celsius


If 1 gram of iron requires 0.11 calories to raise the temperature 1 degree Celsius what is iron's specific heat?

0.11cal/g degrees C


What is the specific heat of 40g of a substance if it requires 195.3 calories of energy to raise its temperature from 5 to 15 degrees Celsius?

488.25 J/kg/*C


If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?

To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.


How many calories are needed to raise the temp of 8.1 g of water 20 degrees Celsius?

The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.