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There are 2 possible digits for the first digit (3 or 4), leaving

3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving

2 possible digits for the third.

Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.

More answers

There are 12.

Q: How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?

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89,999 different numbers i guess

99999

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.

60

10+23 = 33

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89,999 different numbers i guess

If the digits are all different then 18. Otherwise, 192.

2222

You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.

99999

Base two is also referred to as the binary number system.In the decimal system we use 10 different digits (0 to 9) to represent numbers. However, all numbers in binary consist of a combination of only 2 different digits; a "0" and/or a "1".All numbers can be represented using only these 2 digits.

You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.

It is possible to create infinitely many numbers, of infinitely many different lengths, using the digits of the given number. Using each of the digits, and only once, there are 5! = 120 different permutations.

60

10+23 = 33

With base one million, you can create one nonillion different numbers; using the traditional decimal (base ten) system, you can form 100 thousand different numbers.

If they can be repeated, 343 different numbers. If they can be used once each, there are only 210.