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There are 2 possible digits for the first digit (3 or 4), leaving

3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving

2 possible digits for the third.

Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.

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Q: How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
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