It all depends upon how the object is accelerated.
Assuming a constant acceleration so that it reaches 60 mph after 7 seconds starting from stationary:
1 mile = 5280 ft
1 hour = 3600 s
→ 1 mph = 1 mile / 1 hour = 5280 ft / 3600 s = 22/15 ft/s
v = final_velocity = 60 mph = 22/15 ft/s
t = time = 7 s
u = initial velocity = 0
v = u + at
→ v = 0 + at
→ a = v/t = (22/15) / 7
v² = u² + 2as
→ v² = 0 + 2as
→ s = v² / (2a) ft
→ s = (22/15)² / (2 × (22/15) / 7) ft
→ s = (22/15) / (2/7) ft
→ s = 22/15 × 7/2 = 77/15 ft = 5 2/15 ft ≈ 5.13 ft
If you are asking about a car (or other motorised vehicle), then the acceleration is not going to be constant: the vehicle will start accelerating slowly and then accelerate faster. Depending upon the exact shape of the function of the acceleration with relation to time, will change the distance covered.
When traveling at 35 mph it will take you 210 feet to come to a complete stop.
It would take approximately 1,500 feet for an object to reach a speed of 120 mph when free-falling due to the force of gravity.
When traveling at 35 mph it will take you 210 feet to come to a complete stop
Something that travels 100.9 MPH travels 147.99 feet per second. ((100.9 * 5280) / 3600). To travel 60.5 feet would take 0.41 seconds.
The 2007 Yamaha R1 takes approximately 4 seconds to reach 100 mph.
10.49 seconds.
75ft.
228 ft
about 120 ft
151.52 milliseconds.
2.33 minutes.
On dry roads with ABS, around 46 feet.