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It all depends upon how the object is accelerated.

Assuming a constant acceleration so that it reaches 60 mph after 7 seconds starting from stationary:

1 mile = 5280 ft

1 hour = 3600 s

→ 1 mph = 1 mile / 1 hour = 5280 ft / 3600 s = 22/15 ft/s

v = final_velocity = 60 mph = 22/15 ft/s

t = time = 7 s

u = initial velocity = 0

v = u + at

→ v = 0 + at

→ a = v/t = (22/15) / 7

v² = u² + 2as

→ v² = 0 + 2as

→ s = v² / (2a) ft

→ s = (22/15)² / (2 × (22/15) / 7) ft

→ s = (22/15) / (2/7) ft

→ s = 22/15 × 7/2 = 77/15 ft = 5 2/15 ft ≈ 5.13 ft

If you are asking about a car (or other motorised vehicle), then the acceleration is not going to be constant: the vehicle will start accelerating slowly and then accelerate faster. Depending upon the exact shape of the function of the acceleration with relation to time, will change the distance covered.

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8y ago

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More answers

Not enough information. You also need to know at what rate the object in question accelerates.

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8y ago
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Q: How many feet does it take to reach 60 mph in 7 sec.?
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