It all depends upon how the object is accelerated.
Assuming a constant acceleration so that it reaches 60 mph after 7 seconds starting from stationary:
1 mile = 5280 ft
1 hour = 3600 s
→ 1 mph = 1 mile / 1 hour = 5280 ft / 3600 s = 22/15 ft/s
v = final_velocity = 60 mph = 22/15 ft/s
t = time = 7 s
u = initial velocity = 0
v = u + at
→ v = 0 + at
→ a = v/t = (22/15) / 7
v² = u² + 2as
→ v² = 0 + 2as
→ s = v² / (2a) ft
→ s = (22/15)² / (2 × (22/15) / 7) ft
→ s = (22/15) / (2/7) ft
→ s = 22/15 × 7/2 = 77/15 ft = 5 2/15 ft ≈ 5.13 ft
If you are asking about a car (or other motorised vehicle), then the acceleration is not going to be constant: the vehicle will start accelerating slowly and then accelerate faster. Depending upon the exact shape of the function of the acceleration with relation to time, will change the distance covered.
Not enough information. You also need to know at what rate the object in question accelerates.
When traveling at 35 mph it will take you 210 feet to come to a complete stop.
When traveling at 35 mph it will take you 210 feet to come to a complete stop
Something that travels 100.9 MPH travels 147.99 feet per second. ((100.9 * 5280) / 3600). To travel 60.5 feet would take 0.41 seconds.
It takes about 7 seconds to reach 100 mph in 4 gear. You can not reach 100 mph on a Yamaha R1 in 1st gear. It's impossible.
75ft.
10.49 seconds.
2.33 minutes.
228 ft
about 120 ft
151.52 milliseconds.
On dry roads with ABS, around 46 feet.
Assuming uniform acceleration, the speed would be 40 mph and it would take 625 ft to reach 60 mph.