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Oh, dude, you're hitting me with the math questions now? Alright, let's see... So, if we have a 1.5 degree angle over 1 meter, you'd use some trigonometry magic and find out it falls about 26.2 millimeters. But hey, who's really counting, right? Like, just eyeball it and call it a day.
What else can I help you with?
How much fall in a 11 degree roof over 1 meter?
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
How much fall in a 5 degree roof over 6 metres?
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
How much fall in a 3 degree roof over 2 meter?
To calculate the fall (or slope) of a 3-degree roof over a distance of 2 meters, you can use the formula: fall = distance × tan(angle). In this case, the fall would be approximately 2 meters × tan(3 degrees), which equals about 0.105 meters, or 10.5 centimeters. Thus, the roof would fall approximately 10.5 cm over the 2-meter span.
How much fall in 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in a 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in a 8 degree roof over 1 meter?
To calculate the fall (or drop) of an 8-degree roof over a distance of 1 meter, you can use the tangent function from trigonometry. The formula is: fall = distance × tan(angle). For an 8-degree angle, the fall is approximately 1 meter × tan(8°), which equals about 0.14 meters, or 14 centimeters.
How much fall in a 11 degree roof over 1 meter?
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
How much fall in a 5 degree roof over 6 metres?
To calculate the fall over a 5-degree roof pitch over a 6-meter span, you can use the tangent of the angle. The height (fall) is equal to the length multiplied by the tangent of the angle: ( \text{Fall} = 6 , \text{m} \times \tan(5^\circ) ). This results in approximately 0.52 meters, or 52 centimeters of fall over the 6-meter length.
How much fall in a 3 degree roof over 2 meter?
To calculate the fall (or slope) of a 3-degree roof over a distance of 2 meters, you can use the formula: fall = distance × tan(angle). In this case, the fall would be approximately 2 meters × tan(3 degrees), which equals about 0.105 meters, or 10.5 centimeters. Thus, the roof would fall approximately 10.5 cm over the 2-meter span.
How much fall in a 1 degree roof over 1 metre?
1 degree slope = 1.746 centimeter rise or fall in 1 meter of run.
How much fall in a degree roof over 5 meter?
Approx 0.087 metres.
How much fall in a 3 degree roof over 7 meter?
30cm
How much fall in a 2 degree roof over 1 meter?
There are 34.9 mm of fall.
How much fall in a 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in 1 degree roof over 1 meter?
Approx 0.087 metres.
How much fall in a 5 degree roof over 1 meter?
Approx 0.087 metres.
How many mm would a drop be for a 3 degree fall over 1 meter?
It is 52 mm.
