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I'm going to use a method called dimensional analysis to complete this problem. Essentially, you take your original value, and multiply it by complex versions of 1 (The Multiplicative Property of Identity says that you can multiply any number by 1 and not change the value of it).

We all know that 60 minutes are in 1 hour, so how can we put this in the problem?

Well, if we divide any number by 1, we still get the same number back. You'll see how this is useful in a minute.

So we want to make our initial units of hours cancel out and disappear, so we need to make sure that this is in the denominator of our complex form of 1 that we are multiplying by.

1/3 hour x (1 hour / 1 hour)

This is not going to help us much since we still have hours in the numerator afterwards. So, we can substitute in the equivalent number of minutes in the numerator so that we end up with minutes.

1 hour = 60 minutes

1/3 hour x (60minutes / 1 hour) = 1/3 x 60 minutes = 60/3 minutes

= 20 minutes

Your teacher might say to multiply them together, but it's useful to know why multiplying 1/3 and the number of minutes in an hour yields the correct answer.

I hope you understood, and good luck in your future math endeavors!

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15

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109 in 1 3rd of an hour in minuets : o

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10

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10

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dpg

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15 minutes

Q: How many minutes are there in one-third of an hour?

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