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This is the sum S = 105 + 110 + ... + 995

This is a sequence whose nth term is a+r*n where a = 100, r (the common difference) = 5 and n = 1,2,3, ... , 179, so that N = max(n) = 179.

Then S = N *[a + (N+1)*r/2] = 179*[100+180*5/2] = 179*(100+450) = 179*550 = 98450.

Another way to solve this is to work in one-fifths and then multiply the answer by 5 at the end. So,

(1) add all the whole numbers from 1 to 199 (similar to multiples of 5 from 5 to 995);

(2) subtract from this the sum of all whole numbers from 1 to 20 (multiples in subtract 5 to 100) so you are left with the sum of all whole numbers from 21 to 199 (105 to 995);

(3) multiply this answer by 5.

Q: How many multiples of 5 are between 100 and 1000?

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