A palindrome reads the same forwards as backwards.
Therefore the first and last digits must be the same, the second and penultimate the same, and so on.
As 1000 & 3000 both have 4 digits, there are two pairs of digits that must be the same: the first and fourth, the second and third.
The first digit (and hence last digit) can only be 1 or 2 - a choice of 2
The second digit (and hence third digit) can be any of 0, 1, 2, ..., 9 - a choice of 10 for each of the choices of the first/last digit.
Thus there are 2 × 10 = 20 palindromes between 1000 and 3000.
ther are 99 palindromes in between 1 and 1000.
99 palindromes.
99 palindromes.
90 palindromes.
109
ther are 99 palindromes in between 1 and 1000.
99 palindromes.
99 palindromes.
90 palindromes.
There are 17 palindromes between 1 and 1000 that are divisible by 11
There are 10 palindromes divisible by 9 between 1000 and 9999.
109
60 palindromes between 400 and 1,000.
there are 90 palindromes in 100 to 1000 As; 10 palindromes in each 100 and upto 1000, there are 9 hundreds.Therefore; 9 into 10 is equal to 90
11000
think I suppost to know.
99 of them.