Only one. The zeros are there to put the 5 into its proper position; they are not significant digits.
1 of them.
A number with only 1 significant figure can't be rounded to 3 significant figures
e A number that has only 1 significant figure can't be rounded to 3 significant figures
The answer depends on .005 WHAT! There will be a different number on 0.005 inches in an inch compared to the number of 0.005 miles! And since the units have not bothered to say what the units are, it is impossible to give a sensible answer.
5x10-3
0.5 CM
A number with only 1 significant figure can't be rounded to 3 significant figures
e A number that has only 1 significant figure can't be rounded to 3 significant figures
The answer depends on .005 WHAT! There will be a different number on 0.005 inches in an inch compared to the number of 0.005 miles! And since the units have not bothered to say what the units are, it is impossible to give a sensible answer.
Yes, it is.
009 (9) is greater than 005 (5) by 004 (4)
It is 0.500
He is Bibarel.
005 is thicker than 003
five thousandths
5x10-3
Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
.005