How many square feet are in an 18' by 22' by 16' triangle?

Answer 1

I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft.

Given the sides of a triangle, its area is given by:

area = √(s(s - a)(s - b)(s - c))

Where s is the semi-perimeter, ie s = ½(a + b + c)

or triangle with sides 18 ft, 22 ft 16 ft, area is:

s = ½(18 + 22 + 16) ft = 28 ft

→ area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²

Answer 2

Convert everything to feet, then apply Heron's formula.Or apply Heron's formula, then convert from square inches to square feet.