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How many tens all in the number 787?
There are 78.7 tens in the number 787
How many tens in 259?
There are 25 tens in the number 259. This is because the digit 2 represents 20 tens, and the digit 5 represents 5 additional tens. Therefore, when combined, there are a total of 25 tens in the number 259.
How many tens in 1?
Well, isn't that a lovely little question you have there. In the number 1, there are actually zero tens. But that's okay, every number is special in its own way, just like every little tree in our painting.
An example of a proof?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.
How many tens are in 492?
Well, let's take a moment to appreciate the number 492. If we look closely, we can see that there are 49 tens in 492. Isn't that just a happy little discovery? Remember, numbers are just like friends – they're all unique and special in their own way.
How many tens all in the number 787?
There are 78.7 tens in the number 787
How many significant digits are in this number 546?
How many significant digest are in the number 0.0025
How many tens in 259?
There are 25 tens in the number 259. This is because the digit 2 represents 20 tens, and the digit 5 represents 5 additional tens. Therefore, when combined, there are a total of 25 tens in the number 259.
How many games did john worsfold play?
209 - all for West Coast.
How many tens in 1?
Well, isn't that a lovely little question you have there. In the number 1, there are actually zero tens. But that's okay, every number is special in its own way, just like every little tree in our painting.
How many tens are in 2697000?
2697000 ÷ 10 = 269700
How do you round 208930?
It all depends where you are rounding the number to. (ones, tens, hundreds etc.)
Are there an infinite amount of multiples of 11 with an odd digit sum?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.-Sqrxz
An example of a proof?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.
How many neutrons and protons in polonium 209?
84 protons, 84 electrons and 136 neutrons.
It is greater than 47 It has a 4 in the tens place It is an even number?
The only number that satisfies all three of these conditions is 48.
How many hundreds are there altogether in 990 tens?
Well, isn't that a lovely little math puzzle we have here. If we have 990 tens, that means we have 99 hundreds in total. Each hundred is made up of 10 tens, so by dividing 990 by 10, we find our answer - 99 hundreds in all. Happy little numbers, just waiting to be discovered!
