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How many tens all in the number 787?
There are 78.7 tens in the number 787
How many tens in 1?
Well, isn't that a lovely little question you have there. In the number 1, there are actually zero tens. But that's okay, every number is special in its own way, just like every little tree in our painting.
An example of a proof?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.
What is the next number in the number sequence 298 209 129 58 -4?
-57 (each number that is subtracted from the first is 9 different from the previous (i.e. 298-89=209-80=129-71=58-62=-4-53=-57). As you can see, the amounts that are substracted are 89, 80, 71, 62, 53 (all 9 different from the one before it.)
How many integers have a two in the ones and tens place between 0 and 60?
Only one number between 0 and 60 has a two in the ones and tens place, and it's 22. However, if you are looking for all the numbers between 0 and 60 that have a two in EITHER the ones OR tens place, they are 2, 12, 21, 22, 23, 24, 25, 26, 27, 28, 29, 32, 42, and 52.
How many tens all in the number 787?
There are 78.7 tens in the number 787
How many significant digits are in this number 546?
How many significant digest are in the number 0.0025
How many games did john worsfold play?
209 - all for West Coast.
How many tens in 1?
Well, isn't that a lovely little question you have there. In the number 1, there are actually zero tens. But that's okay, every number is special in its own way, just like every little tree in our painting.
How do you round 208930?
It all depends where you are rounding the number to. (ones, tens, hundreds etc.)
Are there an infinite amount of multiples of 11 with an odd digit sum?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.-Sqrxz
An example of a proof?
Are there infinitely many multiples of 11 with an odd digit sum?Yes.One proof [I'm not sure that this is the simplest proof for this, but it is a proof]:--------------------------Note that 209 is divisible by 11 and has an odd digit sum (11). Now consider the number 11000*10i+209. Because 11000 is divisible by 11 and 209 is divisible by 11,11000*10i+209 is divisible by 11 for all whole number values of i (of which there are infinitely many).Further, the digit sum for 11000*10i+209 is odd for all whole number values of i because the hundreds, tens and ones places will always be 2, 0, and 9 respectively, and the other digits will be either all zeros (for i=0) or two ones followed by zeros, down to and including the thousands places. Thus, the digit sum of 11000*10i+209 is 11 for i=0 and 13 for all other whole numbers i.Thus, we have have the following set of numbers (of which there are infinitely many) which are multiples of 11 and which have an odd digit sum:20911209110209110020911000209110000209...----------------[Note there are other multiples of 11 that have an odd digit sum (e.g., 319, 11319, 110319, ...).]___________________________________________________________Late addition:Here is the simplest proof:Prove that x+2=3 implies that x=1.proof:FIRST, assume the hypothesis, that x+2=3. What we try to do is reach the conclusion (x=1) using any means possible. I have some algebra skills, so I'll subtract 2 from both sides, which leads me to x = 1.QED.
How many neutrons and protons in polonium 209?
84 protons, 84 electrons and 136 neutrons.
It is greater than 47 It has a 4 in the tens place It is an even number?
The only number that satisfies all three of these conditions is 48.
How many hundreds are there altogether in 990 tens?
Well, isn't that a lovely little math puzzle we have here. If we have 990 tens, that means we have 99 hundreds in total. Each hundred is made up of 10 tens, so by dividing 990 by 10, we find our answer - 99 hundreds in all. Happy little numbers, just waiting to be discovered!
How many pages does All God's Children Need Traveling Shoes have?
All God's Children Need Traveling Shoes has 209 pages.
How many people use guns to commit a crime using a gun?
Between half and three fourths of people in the US. It is different in other countries.
