10 with 1 remaining 61 - 1 = 60 = 6 x 10
6 with 7 remaining 61 - 7 = 54 = 9 x 6
388 divided by 61 equals 6 with a remainder of 22.
how many times can 8 go into 61
61 - T15, D8
61 ÷ 6 = 10 1/6 = 10.1666... ≈ 10.17
61 ÷ 6 = 10 with remainder 1
9 x 6 = 54 61 - 54 = 7 Answer: 6 times with 7 remaining
61.
10 with 1 remaining 61 - 1 = 60 = 6 x 10
6 with 7 remaining 61 - 7 = 54 = 9 x 6
388 divided by 61 equals 6 with a remainder of 22.
6 times with a remainder of 24
5 with remainder 6.
61 with remainder 6.
9 goes into 61 6 times with 7 left over
how many times can 8 go into 61