0
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits.
If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
Wiki User
∙ 9y ago
Wiki User
∙ 9y ago2^7 = 128 and 2^8 = 256So more than 7 but not more than 8, that is, 8 bits are required.
Add your answer:
Earn +20 pts
How many binary bits are needed to represent decimal number 21?
5
How many bits are required to represent 32 digit decimal number?
103
Number of bits to represent the binary equivalent of the decimal 62?
6 bits 111110 = 32 + 16 + 8 + 4 + 2 + 0
What is the largest positive signed decimal number that can be represented by 8-bits?
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
How does BCD differ from the straight binary number system?
To consider the difference between straight binary and BCD, the binary numbers need to be split up into 4 binary digits (bits) starting from the units. In 4 bits there are 16 possible values from 0000 to 1111 (0 to 15). In straight binary all of these possible combinations are used, thus: 4 bits can represent the decimal numbers 0-15 8 bits can represent the decimal numbers 0-255 12 bits can represent the decimal numbers 0-4095 16 bits can represent the decimal numbers 0-65535 etc In arithmetic, all combinations of bits are used, thus: 0000 1001 + 0001 = 0000 1010 In BCD or Binary Coded Decimal, only the representations of the decimal numbers 0-9 are used (that is 0000 to 1001 in binary), and the 4-bits (nybbles) are read as decimal digits, thus: 4 bits can represent the decimal digits 0-9 8 bits can represent the decimal digits 0-99 12 bits can represent the decimal digits 0-999 16 bits can represent the decimal digits 0-9999 In arithmetic, only the representations of decimal numbers are used, thus: 0000 1001 + 0001 = 0001 0000 When BCD is used each half of a byte is read directly as a decimal digit. BCD is obviously inefficient as storage (for large numbers) as each nybble is only holding 3/8 of the possible numbers, however, it is sometimes easier and quicker to work with decimal digits (for example when there is lots of display of counting numbers to do there is less binary to decimal conversion needing to be done).
How many binary bits are needed to represent decimal number 21?
5
How many bits are needed to represent decimal 200?
8 bits if unsigned, 9 bits if signed
How many bits are needed to represent decimal value ranging from 0 to 12500?
how many bits are needed to represent decimal values ranging from 0 to 12,500?
What is the minimum number of bits required to represent the decimal 1000?
9 bits
how many bits are needed to represent decimal values ranging from 0 to 12,500?
1200
How many bits need to represent the decimal number 200?
8
What is the minimum number if binary bits required to represent the decimal number 250?
8
How many bits are needed to represent the decimal number 200?
8 (assuming unsigned numbers - i.e., you don't reserve a bit for the sign).
How many bits are required to represent 32 digit decimal number?
103
Four bytes can represtent a decimal number between 0 and?
Four bytes represent 32 bits. 32 bits represent 4,294,967,296 possibilities.
What is the minimum number of bits required to represent the following decimal number 101000?
17 bits would allow a value up to 131071.
Number of bits to represent the binary equivalent of the decimal 62?
6 bits 111110 = 32 + 16 + 8 + 4 + 2 + 0
