log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits.
If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
5
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
103
The number of bits needed to represent one symbol depends on the total number of unique symbols. The formula to calculate the number of bits required is ( n = \lceil \log_2(S) \rceil ), where ( S ) is the number of unique symbols. For example, to represent 256 unique symbols, 8 bits are needed, since ( \log_2(256) = 8 ).
6 bits 111110 = 32 + 16 + 8 + 4 + 2 + 0
5
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
8 bits if unsigned, 9 bits if signed
how many bits are needed to represent decimal values ranging from 0 to 12,500?
9 bits
1200
8
8
8 (assuming unsigned numbers - i.e., you don't reserve a bit for the sign).
103
Four bytes represent 32 bits. 32 bits represent 4,294,967,296 possibilities.
17 bits would allow a value up to 131071.