fifty
39 + 25 = 64
39 - 25 = 14
64 - 14 = 50
39 + 25 = 64
39 - 25 = 14
Therefore, the sum is greater than the difference by 50
That's because the integers may be negative. For example, the sum of (-6) and (-6) is (-12), which is less than their difference (0).
No. Consider 0 and 1. Or negative numbers, whose sum produces a smaller number.
Call the numbers "a" and "b": a + b > a - b b > -b 2b > 0 b > 0 In other words, when the second number is greater than zero.
Shouldn't be...
Close. "The whole is more than the sum of its parts."
program SumAndDifference; var num1, num2, sum, difference: integer; begin write('Enter first number: '); read(num1); write('Enter second number: '); read(num2); sum := num1 + num2; difference := num1 - num2; if sum > difference then written('The sum is greater: ', sum) else written('The difference is greater: ', difference); end. This program will prompt the user to enter two numbers, calculate their sum and difference, and then compare the two values. If the sum is greater than the difference, it will display the sum; otherwise, it will display the difference.
It is 155 greater.
That's because the integers may be negative. For example, the sum of (-6) and (-6) is (-12), which is less than their difference (0).
The sum of two decimal numbers greater than 0.5 will always be greater than 1
If the sum of the numerators is greater than the denominator the sum is greater than 1. If the sum of the numerators is equal to the denominator the sum is equal to 1. If the sum of the numerators is less than the denominator the sum is less 1.
The sum is greater than 24.
29.
No. Consider 0 and 1. Or negative numbers, whose sum produces a smaller number.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
3.5 and 7.9846 are two. Their sum is 11.4846 is greater than 1.
No. Example: (3) + (-4) = -1. (3) - (-4) = 7
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