4 R 1
3 times 3 x 13 = 39
39 ÷ 3 = 13
3 and 2/13
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
5 goes into 13 two times with 3 left over.
3 times
3
3 times 3 x 13 = 39
4 times, with 1 left over.
39 ÷ 3 = 13
3 and 2/13
Three (3.6923) times.
Exactly 13 times.
3, remainder 9
Exactly 13 times
Exactly 3 times
Exactly 13 times