If you mean the area, this can be derived in different ways. Most school books should show some derivation of the formula.* It's quite easy to see intuitively (though perhaps a bit more tricky to prove) that the area should be equivalent to the corresponding rectangle, where the width of the rectangle is set equal to the average width of the trapezium. The average, in this case, is the average of the longer and the shorter side (of the two parallel sides). Perhaps the formula was originally derived this way, though it's hard to be sure.
* You can divide a trapezium into rectangles and triangles, and derive the formula from there.
* Of course you could also use integration, though in this case, this is more complicated than necessary.
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The answer depends on what the formula is supposed to refer to: the perimeter, the area, the angle sum?
A trapezium. A trapezium. A trapezium. A trapezium.
Volume = 1/2*(a+b)*h*l where a and b are the lengths of the parallel sides of the trapezium, h is the height of the trapezium, and l is the length of the prism.
Suppose you have a trapezium whose parallel sides (bases) are of lengths A and B units, and where the height is h units If you flip a trapezium over and append it to the original along one of the bases you will have a parallelogram whose base is A+B units in length and whose height is h units. So 2*Area of trapezium = Area of parallelogram = (A + B)*h
has two parallel sideshas four straight linesThe area of the trapezium is given by the following formula where a and b are the lengths of the parallel sides and h is the perpendicular distance between the parallel sides.
Let's call the parallel sides A and B, and the distance between them as H. The area of the trapezium, or K, is (A+B)H/2. K = (A+B)H/2