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How would you find the values of x in the parabolas of y equals 4x2 -12x -3 and y equals x2 plus 11x plus 5 by completing the square?
Wiki User
∙ 6y ago
If: y = 4x^2 -12x -3 and y = x^2 +11x+5
Then: 4x^2 -12x -3 = x^2 +11x+5
Transposing terms: 3x^2 -23x -8 = 0
Dividing all terms by 3: x^2 -23/3x -8/3 = 0
Completing the square: (x-23/6)^2 = 625/36
Square root both sides: x-23/6 = -25/6 or 25/6
Add 23/6 to both sides: x = -1/3 or 8
Therefore the values of x are: -1/3 or 8
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoy1 = 4x2 - 12x - 3 and y2 = x2 + 11x + 5At the point of intersection y1 = y2 so that 3x2 - 23x - 8 = 0
=> x2 - (23/3)x - 8/3 = 0
=> x2 - (23/3)x = 8/3
=> (x - 23/6)2 = 8/3 + (23/6)2 = 8/3 + 529/36 = 625/36
=> x - 23/6 = +/- 25/6
so x = 23/6 +/- 25/6 = -1/3 or x = 8.
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* == == what are the values of square root of x is less than 7 ? ----
