4
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
The area of a trapezoid is equal to half the sum of the lengths of the two parallel sides (base1 and base2) multiplied by the height. The formula for the area of a trapezoid is A = (base1 + base2) * height / 2.
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
-3
11101010.1
If it is a right angled triangle then this is known as Pythagoras' theorem: height2+base2 = hypotenuse2 ⇒ hypotenuse = √(height2 + base2)
Twelve
twelve
this would be 1.31x10^12
12C
12c
Each of its parallel sides is classed as a base
struct base1 { // ... }; struct base2 { // ... }; struct derived1 : public base1 // single inheritance { // ... }; struct derived2 : public base1, public base2 // multiple inheritance { // ... };
the way that you would write twelve hundredths is in this form which is decimal. 0.12 It is: 12/100 or 3/25 in its simplest form
(base1 + base2)/2 = midsegment
A trapezoid is a two-dimensional object. 2d objects do not have volume. To calculate the area, see below. With the parallel sides as base1 and base2, and the distance between them as the height: height*(base1+base2)/2