4
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
The area of a trapezoid is equal to half the sum of the lengths of the two parallel sides (base1 and base2) multiplied by the height. The formula for the area of a trapezoid is A = (base1 + base2) * height / 2.
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
-3
4
this is the question (log (base2) (x))^2- 12(log (base 2) (x)) + 32 = 0, I don't get this bit (log (base2) (x))^2, note the whole log is squared
11101010.1
The area of a trapezoid is equal to half the sum of the lengths of the two parallel sides (base1 and base2) multiplied by the height. The formula for the area of a trapezoid is A = (base1 + base2) * height / 2.
Twelve
If it is a right angled triangle then this is known as Pythagoras' theorem: height2+base2 = hypotenuse2 ⇒ hypotenuse = √(height2 + base2)
Base2 011 = 11 Base3 011 = 10 Any base above that: Base2(11) equals 3
To write 12 more than B, you would write the expression as B + 12. This means you are adding 12 to the value of B.
twelve
-3
To write 12 in Roman numerals, you would use the symbol "XII".
2t/12