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Q: If a rectangles area is 12 cm squared what is the perimeter?

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perimeter = (5+5+12+12)= 34 area = (5*12) = 60 squared

The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.

96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.

The area of a hexagon with a perimeter of 12 units is about 10.4 units2

Thee different rectangles with an area of 12 square units are 3 by 4, 2 by 6 and 1 by 12.

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perimeter = (5+5+12+12)= 34 area = (5*12) = 60 squared

To find the area of a square if the perimeter is given, we must divide it by 4. Here, we have to divide 12 by 4, which is 3. The area of a square is side squared, so that is 3 squared or 9.

The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.

96 units squared. To find area of rectangles, simply multiply the two dimensions (length and width) which in this case are 12 and 8.

the answer is 12

Yes if its dimensions were 3 cm and 12 cm.

If the area of a square is 12 the perimeter is: 13.86

* It is unclear if the question is asking about two rectangles, each with a perimeter of 16, or two rectangles whose perimeters sum to 16. This answer assumes the former.Other than the 4x4 square, which coincidentally has both a perimeter and area of 16, some examples would be:1 x 7 rectangle : perimeter 16 in. , area 7 sq. in2 x 6 rectangle : perimeter 16 in., area 12 sq. in3 x 5 rectangle: perimeter 16 in., area 15 sq. inYou can calculate that for a given perimeter, the largest area is found in the square with a side measurement of P/4, i.e. the length and the width are the same.

12 good guess

If the perimeter is 12, the length of one side must be 12 times 1/4, which is 4. The area of the square is equal to the length of one side squared (which is length times width), which, in this case, is:42 = 4 * 4 = 16 square unitsThe above would be true if 12 times 1/4 was 4, but it isn't, it's 3.Perimeter = length of side x 4. 3 X 4 = 12. The area of a square is length of side squared = 3 X 3 = 9 square units

Yes, rectangles measuring 12x4 and 13x3 have the same perimeter because: 2*(12+4) = 32 meters and 2*(13+3) = 32 meters

The area of a hexagon with a perimeter of 12 units is about 10.4 units2