2
0
if abc is 0 then at least one of the factors must be zero. since a and b are both nonzero, c must be zero.
The integers are -14, -12 and -10.
1
A meter is greater; it is equal to 10 decimeters.
33
if abc is 0 then at least one of the factors must be zero. since a and b are both nonzero, c must be zero.
No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.
There are no "two consecutive integers" that can do that.But there are two consecutive even integers that can: 8 and 10 .
10
The integers are -14, -12 and -10.
integers are x and x + 2, so x + 2 = 2x - 10 ie x = 12. Integers are 12 and 14
It is not possible.
The numbers are 9 and 10.
No. To be divisible by a number it must be greater than, or equal to, that number. 10 is less than 66, so 10 cannot be divisible by 66.
1
10 is equal to 10.
-9 is greater than -10.