pr(six) = 1/6
→ expected 6s in 90 rolls = 1/6 × 90 = 15
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1/6 of 300 = 50 times.
The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.The answer depends on how many times a die is rolled and whether it is a fair die.For a single roll of a fair normal die, the answer is 2/3.
If you were really unlucky, infinitely many times! The probability of that happening is very tiny but it is not zero.
The expected value if you roll a die three times is 3.5.
The expected number of rolls under 3 is the number of rolls times the probability of rolling less than 3. So: E(rolls less than 3 out of 30) = 30 * 1/3 = 30/3 = 10