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If rock at rest falls off a cliff and hits the valley below after 3.5 seconds what is the rocks velocity as it hits the ground?
Wiki User
∙ 15y ago
The final velocity of a falling object can be worked out by the use of the formula a = (v - u)/t a = acceleration due to gravity = 9.8 m.s-2 v = final velocity = unknown u = initial velocity = 0 t = time taken = 3.5s Factor these known values into our equation 9.8 = (v - 0)/3.5 rearrange the formula to workout the unknown value v = 9.8 x 3.5 Final velocity on impact with valley floor = 34.3 m.s-1 with a downwards direction
Wiki User
∙ 15y ago
The velocity of the rock as it hits the ground can be calculated using the formula: velocity = acceleration due to gravity × time taken. Assuming the acceleration due to gravity is -9.81 m/s^2 (negative sign indicates downward motion), the velocity of the rock as it hits the ground would be approximately -34.335 m/s.
Anonymous
9.8 m/s
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Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 5 seconds ago is falling?
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Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 4 seconds ago is falling?
128
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Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 5 seconds ago is falling?
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Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 3 seconds ago is falling?
The rule for calculating the velocity of a falling object is V = gt, where V is velocity, g is the acceleration due to gravity (32 ft/s^2), and t is time. For an object dropped 3 seconds ago, the velocity would be V = 32 ft/s^2 * 3 s = 96 ft/s.
