The quantity supplied the house for forty years.
The decay of plutonium-240 follows exponential decay kinetics, where the amount remaining is given by the equation: N(t) = N0 * e^(-λt), where N(t) is the amount remaining at time t, N0 is the initial amount, λ is the decay constant, and e is the base of the natural logarithm. The decay constant for plutonium-240 is 0.0106 years^-1. By rearranging the equation to solve for time (t) when N(t) = 9 grams and N0 = 27 grams, you can calculate the time it will take for 27 grams of plutonium-240 to decay to 9 grams. The calculated time will be approximately 20.5 years.
(2,000 years) times (1,000 years) = 2 million square yearsThat quantity has no physical significance.
You would have to wait 2,000 years for this to occur. Half of 2,000 is 1,000. Half of 1,000 is 500. This process happens twice. 1,000 years * 2 processes = 2,000 years.
The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.
The plural of 0.01 gram is 0.01 grams. It remains the same because the quantity is less than one gram.
3.002 grams, approx.
It depends on the substance and its rate of decay. The amount remaining can be calculated using the substance's half-life and the initial amount present.
After 100 years, half of the original sample (20 grams) will remain. After another 100 years (total 200 years), only half of that amount (10 grams) will remain.
After 28 years, half of the 2.5 grams (1.25 grams) would remain. After another 28 years (56 years total), only 0.625 grams would remain, and so on. The amount of the radioactive element left can be calculated using the formula: remaining amount = initial amount * (1/2)^(years/half-life), where the initial amount is 2.5 grams and the years is the given time.
The half-life of plutonium-240 is about 6,560 years. To find the time it takes for 36 grams to decay to 12 grams, we can use the formula N = N0 * (1/2)^(t/t1/2), where N is the final amount, N0 is the initial amount, t is the time, and t1/2 is the half-life. Substituting the values, we find that it will take approximately 13,120 years for 36 grams of plutonium-240 to decay to 12 grams.
To find the time it takes for 36 grams of plutonium-240 to decay to 12 grams, we can set up the equation 12 = 36 * e^(-0.00011t) and solve for t. The result is t ≈ 180 years. Therefore, it will take approximately 180 years for 36 grams of plutonium-240 to decay to 12 grams.
Based on the information provided, you can deduce the initial amount of potassium-40 was 10 grams since half of 10 grams is 5 grams. If there are 5 grams left and the half-life is 1.3 billion years, the rock is approximately 2.6 billion years old.
To find the original mass of the cesium-137 sample, you can use the exponential decay formula: final amount = initial amount * (1/2)^(time/half-life). With the information provided, you would have: 12.5 = initial amount * (1/2)^(90.69/30.1). Solving for the initial amount gives you approximately 40 grams.
No, HIV remains hidden in the hosts DNA as a provirus and doesn't start destroying immune cells for many years after the initial infection.
The quantity supplied the house for forty years.
Based on the ratio of 8 grams of radioactive potassium-40 to 56 grams of its nonradioactive decay products, we can infer that half of the initial potassium-40 has decayed. Since the half-life of potassium-40 is about 1.25 billion years, we can estimate the age of the sample to be around 1.25 billion years.