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That depends what assumptions you make about what the 5 grams of matter is made of.

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7y ago
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7y ago

If it is 5 grams of a non-radioactive substance then 5 grams remain.

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Q: If the initial quantity is 5 grams how much remains after 600 years?
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How do you use quantity supplied in a sentence?

The quantity supplied the house for forty years.


How long will it take 27 grams of plutonium-240 to decay to 9 grams?

The decay of plutonium-240 follows exponential decay kinetics, where the amount remaining is given by the equation: N(t) = N0 * e^(-λt), where N(t) is the amount remaining at time t, N0 is the initial amount, λ is the decay constant, and e is the base of the natural logarithm. The decay constant for plutonium-240 is 0.0106 years^-1. By rearranging the equation to solve for time (t) when N(t) = 9 grams and N0 = 27 grams, you can calculate the time it will take for 27 grams of plutonium-240 to decay to 9 grams. The calculated time will be approximately 20.5 years.


2000 years times 1000 years equals?

(2,000 years) times (1,000 years) = 2 million square yearsThat quantity has no physical significance.


How long would it take a radioactive element with a mass of 20 grams to decrease to 5 grams if the half life is 1000 years?

You would have to wait 2,000 years for this to occur. Half of 2,000 is 1,000. Half of 1,000 is 500. This process happens twice. 1,000 years * 2 processes = 2,000 years.


The half life of Radium-226 is 1600 years How many grams will remain from 5 grams after 365 years?

The amount of material left in radioactive decay is an exponential function. Therefore, the way you solve this is to write it as an exponential function; for example: f = e-kt, where "f" is the fraction remaining after a certain time, "t" is the time in any unit you choose (for example, years), and "k" is a constant you have to find out. Replace the numbers you know (for t = 1600 years, f = 1/2, since 1/2 of the original remains), and solve for "k". Then, write the equation again, this time with the constant "k" you figured out before, and the time (365 years). This will give you the fraction left after that amount of time.

Related questions

The plural of 0.01 gram?

The plural of 0.01 gram is 0.01 grams. It remains the same because the quantity is less than one gram.


The radioactive substance Carbon-14 has a half life of 5730 years. After 1000 years there is 2.66 grams remaining. What was the initial amount of the substance?

3.002 grams, approx.


How many grams remain after 20 years?

It depends on the substance and its rate of decay. The amount remaining can be calculated using the substance's half-life and the initial amount present.


A Radio Decay Isotopes Has A Half Life Of 100 Years . A Sample Of 40 Grams Of The Isotopes Will Have A Mass Of Grams In 200 Years?

After 100 years, half of the original sample (20 grams) will remain. After another 100 years (total 200 years), only half of that amount (10 grams) will remain.


A 2.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific Test Site The half-life of the radioactive element is 28 years How much?

After 28 years, half of the 2.5 grams (1.25 grams) would remain. After another 28 years (56 years total), only 0.625 grams would remain, and so on. The amount of the radioactive element left can be calculated using the formula: remaining amount = initial amount * (1/2)^(years/half-life), where the initial amount is 2.5 grams and the years is the given time.


How long will it take 36 grams of plutonium-240 to decay to 12 grams in years?

The half-life of plutonium-240 is about 6,560 years. To find the time it takes for 36 grams to decay to 12 grams, we can use the formula N = N0 * (1/2)^(t/t1/2), where N is the final amount, N0 is the initial amount, t is the time, and t1/2 is the half-life. Substituting the values, we find that it will take approximately 13,120 years for 36 grams of plutonium-240 to decay to 12 grams.


Plutonium-240 decays according to the function Q(t)=Q 0 e^ -kt where Q represents the quantity remaining after t years and k is the decay constant 0.00011 ... To the nearest 10 years , how long will it take 36 grams of plutonium-240 to decay to 12 grams?

To find the time it takes for 36 grams of plutonium-240 to decay to 12 grams, we can set up the equation 12 = 36 * e^(-0.00011t) and solve for t. The result is t ≈ 180 years. Therefore, it will take approximately 180 years for 36 grams of plutonium-240 to decay to 12 grams.


Suppose you find a rock that contains some potassium-40 half-life of 1.3 billion years You measure the amount and determine that there are 5 grams of potassium-40 in the rock By measuring the amount o?

Based on the information provided, you can deduce the initial amount of potassium-40 was 10 grams since half of 10 grams is 5 grams. If there are 5 grams left and the half-life is 1.3 billion years, the rock is approximately 2.6 billion years old.


If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?

To find the original mass of the cesium-137 sample, you can use the exponential decay formula: final amount = initial amount * (1/2)^(time/half-life). With the information provided, you would have: 12.5 = initial amount * (1/2)^(90.69/30.1). Solving for the initial amount gives you approximately 40 grams.


Do white blood cells decrease immediately when hiv plus?

No, HIV remains hidden in the hosts DNA as a provirus and doesn't start destroying immune cells for many years after the initial infection.


How do you use quantity supplied in a sentence?

The quantity supplied the house for forty years.


How old is a sample of granite that contains 8 grams of radioactive potassium-40 and 56 grams of its nonradioactive decay products?

Based on the ratio of 8 grams of radioactive potassium-40 to 56 grams of its nonradioactive decay products, we can infer that half of the initial potassium-40 has decayed. Since the half-life of potassium-40 is about 1.25 billion years, we can estimate the age of the sample to be around 1.25 billion years.