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Assuming the dice are cubes with numbers 1-6 on their faces, the probability that a number less than or equal to 6 is shown is 1 as each die can only show numbers less than or equal to 6.

However, if you mean the SUM of the two dice is less than or equal to 6, then:

There are 36 ways in which the two dice can fall.

The sum of the two top faces can be 2, 3, 4, 5, 6; these are achieved in

2: 1+1 → 1 way

3: 1+2; 2+1 → 2 ways

4: 1+3, 2+2, 3+1 → 3 ways

5: 1+4, 2+3, 3+2, 4+1 → 4 ways

6: 1+5, 2+4, 3+3, 4+2, 5+1 → 5 ways

→ there are 1 + 2 + 3 + 4 + 5 = 15 different ways a sum less than or equal to 6 can be displayed (on the top faces).

Probability_of_success = number_ways_of_success/total_number_of_outcomes

→ Pr(sum ≤ 6) = 15/36 = 5/12

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6y ago
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6y ago

It is 5/12.

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Q: If two dice are rolled what is the probability of getting a number less than or equal to 6?
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