x*2+4x+8= 0 is a quadratic equation
It is a quadratic expression and when factored is: (x+1)(x+1)
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
x*2+4x+8= 0 is a quadratic equation
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
It is a quadratic expression and when factored is: (x+1)(x+1)
No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.
Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.Replace sin2x with the equivalent (1 - cos2x). Simplify, and use the quadratic equation, to solve for cos x.
To solve a quadratic equation (which means to find the zeros of that equation) you have two options 1. type the equation into a graphing calculator and graph the resulting equation and find where the x intercepts are (where y=0) 2. solve the quadratic equation by factoring First, set the equation equal to zero. x2-8x-9=0 Then find the resulting x values by "smiling" multiply the first term and the last term (x2) (9) find two numbers that add to -8 and multiply to -9 these two numbers are -9 and 1 x2- 9x 1x-9 x(x-9) 1(x-9) the resulting factors are 0= (x+1)(x-9) to find the roots, set these factors = 0 x+1=0 x=-1 x-9=0 x=9 Therefore, the solutions for the quadratic equation are x=-1 and x=9
11
Yes it is. The thing that makes it a quadratic equation is that "x squared" in there.
The roots of the quadratic equation are the x-intercepts of the curve.
x2+5x-24 = (x-3)(x+8)
x = 2 and x = 4