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If x chocolates cost 80 and y chocolates cost 60 Find out how many x and y chocolates one can get under the budget of 500?
Wiki User
∙ 6y ago
From the question I interpret x chocolates and y chocolates to be 2 different kinds of chocolates.
Also, there is a slight problem in the interpretation of "under the budget of 500". To be "under" it cannot be equal to, thus the maximum amount that can be spend it 499.99
Which means you could buy:
499.99 ÷ 80 = 6 and a bit → 6 x chocolates and no y chocolates for a cost of 6 × 80 = 480
You could buy 1 less x, leaving 99.99 for y→ 5 x chocolates, 1 y chocolate for a cost of 5 × 80 + 60 = 460
Another 1 less x, leaving 179.99 for y → 4 x chocolates and 2 y chocolates for a cost of 4 × 80 + 2 × 60 = 440. If you were to try to buy another y chocolate (4 x and 3 y) the total would be 500 which is NOT under 500.
Another 1 less x, leaving 259.99 for y → 3 x chocolates and 4 y chocolates for a cost of 3 × 80 + 4 × 60 = 480
Another 1 less x, → 2 x chocolates and 5 y chocolates for a cost of 460
1 x chocolate and 6 y chocolates = 440. If you were to try to buy another y chocolate (1x and 7 y) the total cost would be 500 with it NOT under 500.
0 x chocolates and 8 y chocolates for a cost of 480
There is NO indication in the question of how far under the budget, nor if the maximum of each is bought; thus you can buy any of the following combination of x and y chocolates to be UNDER the budget of 500:
0 x and 0-8 y for a cost of 0 to 480
1 x and 0-6 y for a cost of 80 to 440
2 x and 0-5 y for a cost of 160 to 460
3 x and 0-4 y for a cost of 240 to 480
4 x and 0-2 y for a cost of 320 to 440
5 x and 0-1 y for a cost of 400 to 460
6 x and 0 y for a for of 480
If you were to try to buy 1 x and 7 y or 4 x and 3 y the total cost would be 500 which is NOT UNDER (ie less than) the budget of 500. If the question had stated for a maximum budget of 500, then these combinations could be purchased as the maximum budget of 500 implies less than or equal to the budget of 500.
The maximum would be to buy 0 x and 8 y for a total cost of 480.
If you have to buy at least 1 of each, then 1 x and 6 y for a total cost of 440 would get the most and have the most amount left from the budget.
Wiki User
∙ 6y ago
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