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294 J IS CORRECT

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Lifting a mass does work by opposing the force of gravity, which is a downward acceleration. The work done can be expressed as the product of the mass, height, and the gravitational force that is being opposed. If the distance is in meters, the mass in kilograms, gravity in m/sec2, then the result of the triple product will be in joules (kg-m2/sec2).

Example : W = M x H x g = 30 kg x 1 m x 9.8 m/sec2 = 294 joules.

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Q: If you want to lift a 30-kg box to a height of 1 m how much work will it take?

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To calculate the work required to lift the box, you can use the formula: work = force × distance. In this case, the force is equal to the weight of the box (30 kg * 9.8 m/s^2) and the distance is 1 meter. So the work required would be 294 joules.

The work done to lift the box to a height of 1 m can be calculated using the formula: work = force x distance. In this case, the force required to lift the box against gravity is equal to its weight, which is 30 kg * 9.8 m/s^2 (acceleration due to gravity). The distance is 1 m. Therefore, the work done is 294 joules.

The wing span of the plan has nothing to do with the height of the air craft, it is more in line with weight and length than the height and even then it is mostly has to do with the weight. You see in order to get into the air you need what is called lift. Lift is obtain by passing wind over the wings causing the craft to literally lift of the ground, when you take gravity and the weight of the craft into consideration then you can start looking at the wing span. Now that being said you also must take thrust into consideration. Since you can lift a lot of weight off the ground with smaller wing span if you have enough thrust pushing you forward creating enough wind over/under the wings causing lift. There is still much more answer to this question of wing span but in a nut shell that's it.

The work done to lift the toolbox is calculated as the force (weight of toolbox) multiplied by the distance it moves (height lifted). In this case, the work done will be 6kg (mass of toolbox) * 9.81 m/s^2 (acceleration due to gravity) * 1.5m (height lifted), which equals 88.29 Joules.

It would take 150 kg to lift the load.

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6 feet

15 miniutes

i'm a certified ford technician, it takes me about 3 hours in my shop but I have a lift and the right tools... it could take much much longer without good tools or a lift

around 400

1791.044776119403 cubic feet176 / 0.067 = 1791.044776119403

That depends on the size, shape, and weight of the object, and also on your strength and agility.