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-11r
-9r plus 10r can be written as ( -9r + 10r) and the answer is r.
-1r
10r2 - 29r + 10 = (5r - 2)(2r - 5) when factored Work: First, the trinomial is factorable because ac = 100 = (-25)(-4) and b = -29 = (-25) + (-4). I would like to multiply by 10/10 the trinomial: 10r2 - 29r + 10 = (10/10)(10r2 - 29r + 10) = [(10r - 4)(10r - 25)]/(2)(5) = (5r - 2)(2r - 5)
1180r80s-8