6 yes, 10 no.
186 that it
186 is divisible by all its factors. Factors for 186 are: 1, 2, 3, 6, 31, 62, 93, 186
186 is divisible by: 1, 2, 3, 6, 31, 62, 93, 186
yes evenly giving 31
930 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30, 31, 62, 93, 155, 186, 310, 465, 930.
To determine if 610 is divisible by both 6 and 10, we need to check if it is divisible by both 6 and 10 individually. For 6, we check if 610 is divisible by 2 and 3. Since 610 is even but not divisible by 3, it is not divisible by 6. For 10, we check if 610 ends in 0, which it does not. Therefore, 610 is not divisible by 10 either.
is 510 divisible by 6
Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;
To determine if 410 is divisible by 6, we check if it is divisible by both 2 and 3. It is even, so it is divisible by 2, but the sum of its digits (4 + 1 + 0 = 5) is not divisible by 3, so 410 is not divisible by 6. For 10, since 410 ends in 0, it is divisible by 10. In summary, 410 is divisible by 10 but not by 6.
Yes it is.... 186/2=93 & 186/3=62
0.00007892
Nope.