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Not sure what you mean by "perfect square root".A "perfect square" is the square of a whole number; if that's what you mean, yes, it's the square of the number 1.

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Yes, the square root of 1 is 1.

Q: Is 1 a perfect square root?

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The square root of 1/100 is 1/10 which is a perfect square but perfect square are usually integers.

Yes.One is a perfect square.Because one has square root .sqrt(1)=1,1*1=1

No.1/4 is not a perfect square but its square roots are +/- 1/2 which are rational.

38 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.

A principal square root is any square root that's answer is positive, and a perfect square root is a square root that's answer is an integer.

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The square root of 1/100 is 1/10 which is a perfect square but perfect square are usually integers.

No.1/4 is not a perfect square but its square roots are +/- 1/2 which are rational.

Yes.One is a perfect square.Because one has square root .sqrt(1)=1,1*1=1

200 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.

345 is not a perfect square and neither is its square root.

30 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.

500 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.

38 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.

I suppose you mean a perfect square. The answer is 25.

A principal square root is any square root that's answer is positive, and a perfect square root is a square root that's answer is an integer.

16 is a perfect square (of 4) and the square root of 256.

There is no formula relating to a perfect square but if you want a method 1. Find square root(x) 2. Take the integer component (integral value) of square root(x) 3 Add 1 to intenger(square root(x)) 4. square it So: (integer(square root(x)) + 1)^2