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Q: Is 1 k greater then 1200 g?

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If delta G is negative, then K (Upper case K, as in Keq or the equilibrium constant) will be greater than 1. Remember that delta G = -RT log K.Do not get Keq confused with lower case k, which denotes rate constants (which have NOTHING TO DO WITH Keq or delta G).

air does it has 1.01 J/g-K and water has 1.00 J/g-K

1 kg = 1000 grams. The prefix "kilo" - here abbreviated as "k" - means 1000.

The density of molten copper at 1200 0C is near 7,898 g/cm3. An empirical formula is: d (g/cm3) = 9,077 - 8,006.10-4 T (in K)

The atomic mass of potassium is 39.10 g/mol. 1.90 mol K * (39.10 g K / 1 mol K) = 74.3 g K

It could be a g.

In general, the transfer function of closed loop system is (Y/X)=G*K/(1+G*K*H) ----- negative feedback (Y/X)=G*K/(1-G*K*H) ----- positive feedback where G- transfer function of the plant 0r system K - controller H - feedback transfer function Y-output in laplace domain X-reference in laplace domain so the transfer function of the closed loop system with unity feedback is so H=1(unity) (Y/X)=G*K/(1+G*K) ------- negative feedback (Y/X)=G*K/(1-G*K) ------- positive feedback if u couldn't understand notify me... i will improve it

(4.1813 J x g-1 K-1) x (18.0153 g mol-1) = 75.327 J mol-1 K-1

(4.1813 J x g-1 K-1) x (18.0153 g mol-1) = 75.327 J mol-1 K-1

449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)

1. 4.8 g of KCL 2. 2.1 g of KCL

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