345 is divisible by: 1 3 5 15 23 69 115 and 345.
3 + 4 + 5 = 12 which is not divisible by 9, so 345 is not divisible by 9.
1, 3, 5, 15, 23, 69, 115, 345.
No, and the first give-away is that it ends in 5 (divisible by 5).
No. Numbers that are divisible by 2 must end in an even number (0,2,4,6,8)
345 is divisible by: 1 3 5 15 23 69 115 and 345.
3 + 4 + 5 = 12 which is not divisible by 9, so 345 is not divisible by 9.
5
1, 3, 5, 15, 23, 69, 115, 345.
345 and 218
12 345
No, and the first give-away is that it ends in 5 (divisible by 5).
For each given number, add the digits. If the sum comes to nine, then it is divisible by '9'. 234 ; 2 + 3 + 4 = 9 So is dividble by '9' 345 ; 3 + 4 + 5 = 12 = 1 + 2 = 3 Not divisible by '9' 567 ; 5 + 6 + 7 = 18 = 1 + 8 = 9 so is divisible by '9'.
No. Numbers that are divisible by 2 must end in an even number (0,2,4,6,8)
Itself because 345/345 = 1
They are: 345, 690 and 1035
All multiples of 345, which is an infinite number.