Not exactly because it will have a remainder
No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
no. its divisible by 2 and 10
61.25
7 is a factor of 490 but 8 is not.
1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490.
Any multiple of 490.
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
Composite; any number ending with zero (besides zero itself) is divisible by 10. 490 = 49 * 10 = 7 * 7 * 5 * 2
Neither is divisible by 8.