No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
4 is divisible by 1, 2 and 4. So is 8. If a number is divisible by 8, it will also be divisible by 4.
No, it's not.
No, it is divisible by 1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490
no. its divisible by 2 and 10
61.25
7 is a factor of 490 but 8 is not.
1, 2, 5, 7, 10, 14, 35, 49, 70, 98, 245, 490.
490 ÷ 58 = 8 times remainder 26, alternatively, using fractions and decimals: 490 ÷ 58 = 8 13/29 ≈ 8.448
If the last 3 digits are divisible by 8, the number is divisible by 8.
no.. for example 6,12,18 are divisible by 2..but not divisible by 8.
Composite; any number ending with zero (besides zero itself) is divisible by 10. 490 = 49 * 10 = 7 * 7 * 5 * 2
152 is divisible by 8, and the answer is 19.
Neither is divisible by 8.