It is even.
100 is an even number.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 100 is an even number.
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
There are 101 numbers between 0 and 100. Because it starts with an even number and ends with an even number, there is 1 less odd number than even. So 51 even and 50 odd.
The sum of 5 odd numbers must be odd and 100 is even. So there cannot be such a set.
No most are odd nos.
Odd. Even + Even = Even Odd + Odd = Even Odd + Even = Even + Odd = Odd
An even number is divisible by 2. Odd numbers are not divisible by 2. Therefore, 100 is an even number.
In Java:System.out.println("Even numbers")for (int i = 2; i