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Yes. Because an example of this would be 15 ÷ 4 2/3. To solve you would turn 4 2/3 to 14/3 and 15 to 15/1. Then u multiply to get 210/3. 210/3 simplified is 70. And 70 is greater than 15 so yes, yes u can divide by a mixed number to get a quotient greater than 15. If you came to the conclusion that no you can not. Did you test your reasoning?
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Is it possible to divide 15 by a mixed number and get a qoutient that is greater then 15-?
No, it is not possible to divide 15 by a mixed number and get a quotient that is greater than 15.
What is the qoutient of a number and 10 is greater than 82?
x/10 > 82 x > 820
Qoutient of a number and 50?
The quotient of 50 and a number is 2.
Is it possible to divide 15 by a number and get a quotient that is greater than 15?
By an integer, no. By any proper fraction, yes.
Is 0 over 2 possible?
yes, it is possible to divide zero by a number. It is not possible to divide a number by zero though, which is undefined.
What will happen if you divide a fraction?
If you divide the fraction by a number greater than 1 then you will have a smaller fraction.If you divide the fraction by a number equal to 1 then you will have the same fraction.If you divide the fraction by a positive number smaller than 1 then you will have a greater fraction.
Can you divide 15 by a mixed number and get answer greater than 15?
No, you can't divide 15 by a number greater than 1 and get an answer greater than 15. All mixed numbers are greater than 1 by definition.
Is it possible for a negative number to be greater thatn a positive number?
this is not possible
When you divide a whole number by a fraction less than one will the quotient be greater than or less than the whole number?
When you divide a number by a fraction between zero and one, the quotient will be greater than that number.
When you divide a number by 3?
if it's possible
Is it possible to divide the number 106?
1,2,53,106
When you divide a mixed number by a fraction less than 1 will the quotient be greater or less than the whole number?
It will be greater.
