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To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2.

To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3.

To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5.

To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9.

26 is divisible by 2 but not divisible by 3, 5 nor 9.

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Q: Is the number 26 divisible by 2 3 5 or 9 How do you know?

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It is 2 because any even number is always divisible by 2 with no remainder.

No. 26 is divisible by 2 and 13.

2 yes, the rest no.

the number will also be divisible by 3 and 2

If a number is even, it's divisible by two.

Out of all those possible numbers - 26 is only divisible by the number 2 !

The only common factors I can see are 1 and 2. 18 is divisible by 1,2,3,6, and 9, and 26 is divisible by 1,2,13,and 26.

When ever it is an even number

26 is divisible by any of its factors which are: 1, 2, 13 and 26.

It's divisible by 2 because, you know divisible means with a 0 in the number. So look at the number 620123 there's a 0 on the third number. That was why it is divisible. So, just remember that.

A number is considered odd when it is not divisible by 2.

no. there is a trick to know if something is divisible by 2 and that is, if the number ends in a 2,4,6,8, or 0 it is divisible by 2 hope this helps. vvk

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