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True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.

If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.

Repeat, each time subtracting the smaller number from the bigger.

Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.

GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.

True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.

If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.

Repeat, each time subtracting the smaller number from the bigger.

Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.

GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.

True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.

If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.

Repeat, each time subtracting the smaller number from the bigger.

Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.

GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.

True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.

If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.

Repeat, each time subtracting the smaller number from the bigger.

Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.

GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.

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11y ago

True, and this property is useful for finding the greatest common factor (GCF) of two (or more) large numbers.

If A > B, then GCF(A , B) = GCF(A - B, B) where A - B is smaller than A.

Repeat, each time subtracting the smaller number from the bigger.

Keep going until both numbers in the parentheses are the same: that number is the GCF of A and B.

GCF by subtraction rather than factorising or division. Unfortunately, it can be quite slow. You could speed it up by doing A - 2B or A - 3B etc rather than A - B.

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Q: Is this true or false ' if 2 numbers are each divisible by another number then their difference is also divisible by that number'?
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