Java code to find the sum in all integer?

Answer 1

The following will sum all integers from 1-100. Adjust according to your needs.

int sum = 0;
for (int i = 1; i <= 100; i++) sum += i;
System.out.println("The sum is " + sum);

The following will sum all integers from 1-100. Adjust according to your needs.

int sum = 0;
for (int i = 1; i <= 100; i++) sum += i;
System.out.println("The sum is " + sum);

The following will sum all integers from 1-100. Adjust according to your needs.

int sum = 0;
for (int i = 1; i <= 100; i++) sum += i;
System.out.println("The sum is " + sum);

The following will sum all integers from 1-100. Adjust according to your needs.

int sum = 0;
for (int i = 1; i <= 100; i++) sum += i;
System.out.println("The sum is " + sum);

Answer 2

import java.io.*;

class TwoD

{

protected static void main()throws IOException

{

BufferedReader in=new BufferedReader(new InputStreamReader(System.in));

System.out.print("Enter the no. of Elements: ");

byte a=Byte.parseByte(in.readLine());

int ar[]=new int[a];

long sum=0;

for(byte i=0;i<a;i++)

{

System.out.print("Enter the value of ar[ "+i+" ]: ");

ar[i]=Integer.parseInt(in.readLine());

}

for(byte i=0;i<a;i++)

sum+=ar[i];

System.out.print("Sum= "+sum);

}

}

Answer 3

The following will sum all integers from 1-100. Adjust according to your needs.

int sum = 0;
for (int i = 1; i <= 100; i++) sum += i;
System.out.println("The sum is " + sum);

Answer 4

You loop through all the elements in the array. Something like this:

sum = 0;

for (i = 0; i<= myArray.length()) {

sum += myArray[i];

}