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You have to make a system of equations, s=solid rolls and p=patterned rolls:

S + P = 480

S4 + P6 = 2340 Solve for either P or S in the first equation, P = 480-S

Then put into the second equation. 4S + 6(480-S) = 2340

Solve. I cant find it!

I already did the formula THREE times! I need a clue on how to do it. What I did is... 4e +6(480 +e) = 2340 It's the same formula that is shown in my book, it wont come out right.

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12y ago

There's a lot of subjective elements involved. However, my personal experience is that the Nicholas Kirkwoods brand is the most comfortable around.

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Q: MATH QUESTION How many solid rolls and patterned rolls are sold if solid is 4 dollars and patterned is 6 dollars and total sums is 2340 dollars and only 480 rolls are sold HOW MANY OF EACH ROLLS?
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MATH QUESTION how many solid rolls and patterned rolls are sold if solid is 4 dollars and patterned is 6 dollars and the total sums is 2340 and only 480 rolls are sold HOW MANY FOR EACH ROLL?

I cant find it, what I did is the formula from my math book and so I did... 4e +6(480+e) = 2340 It's not coming out, I'm not sure what I'm doing wrong so if someone reads this and knows the correct formula, tell me it but I will find the answer please. Try this. (Eq.1) 4x +6y = 2340, x + y = 480 so that (Eq.2) y = 480 - x, Substitute this value of y into (Eq.1) and the result is x = 270. Subtract this value of x from 480 to obtain y = 210. Then check your answer 210x6 +240x4 = 2340.


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