1, 2 and 3
1,2,3
1,2 and 3
6 12 18
answer is 1 2 3
1,2,3
2
s
8
123
Can't be done. The number has to be a multiple of 3.
Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.
13 is a prime number. 13, like every other prime number, has only two factors. The factors of 13 are 1 and 13. Any multiple of any number greater than one would have at least three factors: 1, the number, and the number it is a multiple of.
70
Calculate the least common multiple of the three numbers. Any multiple of that has all those numbers as factors.
4 is a multiple of three numbers.
I'll guess those are three-digit numbers. The way to find if a number is a multiple of 3 is to total its digits. If that total is a multiple of 3, the whole number is a multiple of 3. 285 and 126, yes. 770, 176, 410, 452, 650, no.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Can't be done. The number has to be a multiple of 3.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.
The three numbers go into any integer multiple of 880.
79
70
13 is a prime number. 13, like every other prime number, has only two factors. The factors of 13 are 1 and 13. Any multiple of any number greater than one would have at least three factors: 1, the number, and the number it is a multiple of.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
The third number could be: 3, 6, 15 or 30