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14y ago

No solution in integers, quadratic formula gives roots as 5.875 & -1.875

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Q: Solve x squared minus 4 x-11 for x?
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What is the answer to 2x squared minus 4?

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How do you solve X squared minus four for x equals 3?

Your Problem: X - 4 = ?Current Problem: 3 [squared] - 4 = ?How: When a numbered is squared, it means you multiply it against itself. So, 3 squared equals 3x3.3x3 = 9So, you would then take 9 and minus it by 4, which would than equal 5.Answer:3 [squared] - 4 = 5or9 - 4 = 5


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So u have the function x2-4=0 Now because 4 is a squared number, its square root is 2 (x+2)(x-2)=0


When you subtract one square number from another and the number is 12 what are the two square numbers?

The answer is 4 squared minus 2 squared as 4 squared is 16 minus 2 squared, which is 4, gives you 12 as an answer.


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Factors of -8 are -1 & 8, -2 & 4, -4 & 2 and -8 & 1. Only -4 & 2 add to -2 so factors are (x + 2)(x - 4)


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How would you solve x squared minus 3x minus 15 equals 0?

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What is the constant in this expression 3 x squared minus 2 x y minus 4?

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