Dividend
The sum of 54 and 63 is 117. This can be expressed as the product of 9 and 13, where 9 and 13 are relatively prime addends. Therefore, 54 + 63 = 9 × 13.
Addends are the numbers that are combined to create a sum. For the sum of 50, any pair of numbers that, when added together, equals 50 can be considered addends. For example, 20 and 30, or 25 and 25 are both sets of addends that sum to 50. There are infinitely many combinations of addends that can achieve this sum.
in the equation 3+4=7, 3 and 4 are the addends. 7 is the sum.
The sum of a set of addends whose sign is the same is the sum of the absolute values of the addends with the same sign as the addends.
The sum could be anything, but it would be a positive number if the two addends are positive.
True.
The sum of 54 and 63 is 117. This can be expressed as the product of 9 and 13, where 9 and 13 are relatively prime addends. Therefore, 54 + 63 = 9 × 13.
Addends are the numbers that are combined to create a sum. For the sum of 50, any pair of numbers that, when added together, equals 50 can be considered addends. For example, 20 and 30, or 25 and 25 are both sets of addends that sum to 50. There are infinitely many combinations of addends that can achieve this sum.
in the equation 3+4=7, 3 and 4 are the addends. 7 is the sum.
The sum of a set of addends whose sign is the same is the sum of the absolute values of the addends with the same sign as the addends.
The sum could be anything, but it would be a positive number if the two addends are positive.
You add two addends to get a sum. For example, in 3 + 5 = 8, 3 and 5 are addends, and 8 is the sum.
Start with the product. There are fewer factors than addends.1,3602,1803,1204,905,726,608,459,4010,3612,30 We have a winner!!!15,2418,20
The sum of addends 11 and 15 is: 11 + 15 = 26
The Answer will be lower the the actual sum
i am a sum. my addends are five different whole numbers. all my addends are greater than zero and less than eleven. all my addends are odd numbers. what am i?
The sum of a set of numbers divided by the number of addends is the mean average of that set.