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The (blank) of a complex number z=r(cos(theta) + i * sin(theta)) is the angle theta?
Argument
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How do you convret polar form of complex number into algebraic form?
For a complex number in polar form with Magnitude, and Angle: (Magnitude)*(cos(angle) + i*sin(angle)) will give the form: a + bi
How do you find square root of a complex number?
This is best done if the complex number is in polar coordinates - that is, a distance from the origin, and an angle. Take the square root of the argument (the absolute value) of the complex number; and half the angle.
A complex number is a number of the form a plus bi where?
"a + bi" is a common way to write a complex number. Here, "a" and "b" are real numbers.Another common way to write a complex number is in polar coordinates - basically specifying the distance from zero, and an angle.
What complex number is a number of the form a plus bi where?
"a + bi" is a common way to write a complex number. Here, "a" and "b" are real numbers.Another common way to write a complex number is in polar coordinates - basically specifying the distance from zero, and an angle.
How can you reconstruct a complex number given the amplitude and phase?
A complex number of the form M /_ÆŸ (Magnitude and angle ÆŸ), can be converted to the format {a + bi} as follows: M*(cosÆŸ + isinÆŸ)
What is the strategy for finding the cube root of complex numbers?
Here's how you can find any power (fractions would be a root of a number) of any number (complex or real). A real number is a subset of the complex number set, with the imaginary part = 0. I'll refer you to a related link on Euler's formula for information about how this is derived. A complex number can be graphed on the Real-Imaginary plane, with reals on the horizontal axis, and imaginary on the vertical. Convert the complex number from x-y style coordinates in this plane to polar coordinates.For a complex number a + bi, here's how you do that. We will end up with a magnitude and an angle. The magnitude is sqrt(a² + b²). The angle is found by tan-1(b/a). Now to find a power, apply the power to the magnitude (for cube root this is exponent of 1/3). Then multiply the angle by the power (in this case you divide by 3). Really for a cube root there will be 3 distinct roots. Since a the angle of a circle is 360° or 2pi radians, you can add 2pi radians to the angle of the original complex number, then divide by 3 to determine the second root. Add 4pi radians to the original angle and then divide by 3 to determine the 3rd root. Then convert back to x-y coordinates if you want to:Magnitude*(cos(angle) + i*sin(angle)), for each of the 3 angles that you determined.See the question: 'Strategy for finding the cube root of complex numbers'Strategy_for_finding_the_cube_root_of_complex_numbers
What are the parts of a complex number?
A complex number can be thought of as a vector with two components, called the "real part" (usually represented on the horizontal axis), and the "imaginary part" (usually represented on the vertical axis). You can also express the complex number in polar form, that is, with a a length and an angle.
Conjugate and a complex number equal?
The conjugate will have equal magnitude. The angle from the real axis will be the same angle measure (but opposite direction).
Are complex numbers closed for finding the square root of a number?
Yes. Also, for finding any other root (cubic root, fourth root, etc.). The main square root of a complex number can be found easily if it is expressed in polar notation. For example: the square root of 5 at an angle of 46 degrees) the complex number that has the absolute value 5 and an angle of 46 degrees) is equal to the square root of 5, at an angle of 46/2 = 23 degrees.
How can you square a complex number in trigonometric form?
Multiply the angle by 2, and square the magnitude. The angle can be rewritten between (-180° & +180°) (or -pi and +pi radians), after multiplying.
What angle does a star have?
It doesn't. It's a complex polygon with re-entrant sidesso has a number of angles depending on its shape.
Can you take the log of an imaginary number?
Yes, you can take the logarithm of an imaginary number, but it's more complex than with real numbers. The logarithm of a complex number, including imaginary numbers, is defined using the polar form of the number. For an imaginary number like ( bi ) (where ( b ) is real), the logarithm can be expressed as ( \ln|b| + i\arg(b) ), where ( \arg(b) ) is the argument (angle) of the complex number in the complex plane. Thus, the result will also be a complex number.
