The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
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The difference of c and 5 is simply c - 5. This can't be simplified, unless you assume a specific value for c.
22 - 5 = 17 degrees
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
The -7 is called the difference. In any subtraction problem: a = b - c a is the difference b and c are terms (technically, b is minuend and c is subtrahend, but these terms are not really used in modern math)
If you are you refering to temperature scales Celcius and Fahrenheit, then the crossing of the two scales happens at -40 degrees. That is because of a 32 degree difference at freezing point of water and the F-scale is 5/9ths of the C-scale. C = (F - 32) * 5/9 and F = (C * 9/5) + 32 so -40 = (-40 * 9/5) + 32 = -40
F to C- Deduct 32, then multiply by 5, then divide by 9 C to F- Multiply by 9, then divide by 5, then add 32 This is how you find Celsius to Fahrenheit and Fahrenheit to Celsius.