83
simple answer:
+/- 5
long worked answer:
let x = one of the numbers
y = other number
x+y = 17
xy = 66
solve for y
y = 17 - x
plug it in
x(17-x) = 66
multiply it out
17x - x^2 = 66
rearrange and multiply both sides by -1
x^2 - 17x + 66 = 0
factor
(x - 6) (x - 11) = 0
for the left side to equal the right, x must equal either 6 or 11
plug back in to solve for y
y = 17 - x
so y = 17 - 6 = 11
or 17 - 11 = 6
so if x = 6, y = 11
and if x = 11, y = 6
since the question is what is answer if you take one away from the other...
it's either 11 - 6 or 6 - 11, giving 5 or -5.
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It is prime because only 1 and 71 multiply together to get 71. No other whole numbers multiply to equal 71.
You can multiply the first two numbers, then multiply the result with the third number. Or multiply in any other order.You can multiply the first two numbers, then multiply the result with the third number. Or multiply in any other order.You can multiply the first two numbers, then multiply the result with the third number. Or multiply in any other order.You can multiply the first two numbers, then multiply the result with the third number. Or multiply in any other order.
Multiply all the numbers together and then add 1.
Given that the total you are looking for is even, and that you are looking for three numbers in your solution, one of the numbers has to be 2 - otherwise, three odd numbers added together would always equal an odd number. The other two numbers in the sum are 37 and 61.
Multiplicands.
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In grade school when you multiply two numbers by putting one below the other,the top number is called the multiplicand and the bottom one the multiplier.In algebraic expression such as 2xy, the numbers multiplied together are called factors.