3 * 5 * 7 = 105
The LCM of a set of primes is the product of the members of the set so LCM(3,5,7) = 3*5*7 = 105
There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.
The prime factors of 5,145 are: 3 5 7. So, 3 x 5 x 7 = 105.
The products of the primes are the composites.
1450 as a product of primes = 2 * 5 * 5 * 29
20 as a product of primes = 2 * 2 * 5
There is only one lowest common factor for primes: 1 All three numbers are prime, so the LCM is going to be their product: 105 ■
95 is the product of two primes, 5 and 19.
To express 2625 as a product of its primes, we start by dividing it by the smallest prime numbers. Dividing by 5 gives us 525, and dividing 525 by 5 again gives us 105. Next, dividing 105 by 5 results in 21, and finally, dividing 21 by 3 gives us 7, which is also a prime. Thus, the prime factorization of 2625 is (5^3 \times 3 \times 7).
All pairs of two primes are coprime. There are fifteen primes under 50. So that means there are 105 unique pairs of "coprime primes", or more generally, pairs of primes, under 50.
(105) = 3 * (35) = 5 * 7 (both primes, end)so, prime factors of 105 : 3,5,7(175) = 5 * (35) = 5 * 7 (both primes, end)so, prime factors of 175 : 5,5,7
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