6 multiplied by 4/5 is 4 4/5
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 6 6 6 6 6 6As shown above, a digit is repeated to match the value of that digit.
There are 216 permutations of three standard dice. Of these, there are exactly 10 that sum to 15, namely 3-3-6, 4-5-6, 4-6-5, 5-4-6, 5-5-5, 5-6-4, 6-3-6, 6-4-5, 6-5-4, and 6-6-3. The probability, then, of rolling a sum of 15 with three standard dice is 10 in 216, or 5 in 108, or about 0.04630.
Since your question is as ambiguous as it is trivial I will answer all possible interpretations: 6*8+4/5 = 48+4/5 6*(8+4/5) = 52+4/5 6*(8+4)/5 = 14+2/5 (6*8+4)/5 = 10+2/5
4 x 5/6 = 3 1/3 or three and one third.
4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4 7 -7 -6 6 -7 6 -6 -5 6 7 -7 -6 6 -7 7 -7 -6 6 -7 6 -6 -5 6 5 -5 5 4 4 4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4
6*4/5 = 24/5 = 44/5 or 4.8
(1, 5, 6, 6), (2, 4, 6, 6), (2, 5, 5, 6), (3, 3, 6, 6), (3, 4, 5, 6), (3, 5, 5, 5), (4, 4, 4, 6), (4, 4, 5, 5).
5
4* 1 4*2 4*3 4*5 5*1 5*2 5*3 5*4 5*5\ 6*16*2 6*3 6* 4 6*5
6 / (4/5) = 6 * (5/4) = 30/4 = 15/2 or 7.5
(15/4) / (6/5) = (15/4) * (5/6) = (15*5)/(4*6) = 25/8
4*5, 4*6 and 5*6
The ratio is 4:5:6.
Average of 4, 5 and 6 = (4+5+6)/3 = 15/3 = 5
4 + 6 + 6 + 5 + 5 + 4 + 6 + 5 + 5 + 6 + 5 + 5 + 5 + 3 = 70
5/6 × 4 = 5/6 × 4/1 = (5×4)/(6×1) = 20/6 = 10/3 = 3 1/3