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6 multiplied by 4/5 is 4 4/5
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5 6 6 6 6 6 6As shown above, a digit is repeated to match the value of that digit.
There are 216 permutations of three standard dice. Of these, there are exactly 10 that sum to 15, namely 3-3-6, 4-5-6, 4-6-5, 5-4-6, 5-5-5, 5-6-4, 6-3-6, 6-4-5, 6-5-4, and 6-6-3. The probability, then, of rolling a sum of 15 with three standard dice is 10 in 216, or 5 in 108, or about 0.04630.
Since your question is as ambiguous as it is trivial I will answer all possible interpretations: 6*8+4/5 = 48+4/5 6*(8+4/5) = 52+4/5 6*(8+4)/5 = 14+2/5 (6*8+4)/5 = 10+2/5
The modes are 2, 3, 4, 5 and 6.